Question

if diagonal of a square is
$\sqrt{2}$
cm then the perimeter of a square is ....cm

​

Answer 1

Step-by-step explanation:

Given,

Diagonal of a Square = $\sf\sqrt{2}$cm

To Find :-

Perimeter of the Square

Solution :-

We know that :-

Diagonal of a Square = $\sf\sqrt{2}\times$Side of a Square.

According to Question , Diagonal of a Square = $\sf\sqrt{2}$cm

$\implies \sqrt{2} = \sqrt{ 2} \times side$

$side = \dfrac{ \sqrt{2} }{ \sqrt{2} }$

side = 1cm

Since, Side of a Square = 1cm

Formula Required :-

Perimeter of a Square = 4$\sf\times$Side of a Square

$= 4 \times 1cm$

= 4cm

$\sf\therefore$ Perimeter of a Square = 4cm