if diagonals of a cyclic quadrilateral are diameters of the circle through the vertices of the quadrilateral prove that it is a rectangle
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proved
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Draw a cyclic quadrilateral ABCD inside a circle with center O such that its
diagonal AC and BD are two diameters of the circle.
We know that the angles in the semi-circle are equal.
So, ∠ ABC = ∠ BCD = ∠ CDA = ∠ DAB = 90°
So, as each internal angle is 90°, it can be said that the quadrilateral ABCD is a
rectangle.
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