If diagonals of a cyclic quadrilateral are diameters of the circles through the vertices of the
quadrilateral, prove that it is a rectangle.
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Here, ABCD is a cyclic quadrilateral in which AC and BD are diameters .
Since AC is a diameter.
∴ ∠ABC = ∠ADC = 90°
[∵ angle of a semicircle = 90°]
Also, BD is a diameter
∴∠BAD = ∠BCD = 90°
[∵ angle of a semicircle = 90°]
Now, all the angles of a cyclic quadrilateral ABCD are 90° each.
Hence, ABCD is a rectangle.
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