If diagonals of a quadrilateral are equal then show that the figure is a rectangle
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Answer:
Sol: A parallelogram ABCD such that AC = BD In ΔABC and ΔDCB,
AC = DB
[Given]
AB = DC
[Opposite sides of a parallelogram]
BC = CB
[Common]
ΔABC = ΔDCB
[SSS criteria]
∴Their corresponding parts are equal.
⇒∠ABC = ∠DCB
...(1)
∵AB || DC and BC is a transversal.
[∵ ABCD is a parallelogram]
∴∠ABC + ∠DCB = 180°
...(2)
From (1) and (2), we have
∠ABC = ∠DCB = 90°
i.e. ABCD is parallelogram having an angle equal to 90°.
∴ABCD is a rectangle.
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Answer : If the diagonals of a parallelogram are equal, then show that it is a rectangle. ... ∴ABCD is a rectangle. Q3. Show that if the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus.
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