Question

If diagonals of a rhombus are 18cm and 24 cm respectively, then its side is equal to​

Answer 1

Question

If diagonals of a rhombus are 18cm and 24 cm respectively, then its side is equal to

Solution

$\sf→ AD^2=AO^2+OD^2\\ \tt→ AD^2=9^2+12^2\\ \sf→AD^2=81+144\\ \tt→ AD^2=225\\ \sf→ AD=\sqrt{225}\\ \tt→ AD=15cm$

Similarly,

• BC = CD = AB = 15 cm

Let,

• The side of rhombus be 'a' cm

Then ,

• a ( side ) = 15 cm
• Perimeter of Rhombus = 4a where , a = side

$\sf → perimeter = 4a\\ \tt→ perimeter = 4×15\\ \sf→ perimeter = 60cm^2$

Therefore ,

• Area of rhombus = 1/2 × ᵈ1 × ᵈ2

$\sf → Area = \dfrac{1}{2}×18×24\\ \tt→Area = \dfrac{1}{2}×432\\ \sf→Area = \dfrac{\cancel{432_{216}}}{\cancel{2}}\\ \tt→ Area = 216cm^2$

_________________________

Hence,

• The side is equal to 15cm

Answer 2

Step-by-step explanation:

ad²=ao²+od²

ad=9²+12²

ad=81+144

ad²=225

ad=15 cm

similarly

bc=ld=ad

15 cm

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