Question

If diagonals of a rhombus are 36 cm and 48 cm, then what is the perimeter (in cm) of the rhombus

Answer 1

see, the formula for the perimeter of a rhombus is 4*side
So you have to find the side of the rhombus by using Pythagoras theorem.
Hypotenuse^2=Base^2+Perpendicular^2
H^2=36*36+48*48
=1296+2304=3600
H=√3600=60cm
so perimeter=4*60=240

Answer 2

Step-by-step explanation:

Using the formulas

P=4a

a=p2+q2

2

Solving forP

P=2p2+q2=2·362+482=120cm