Question

if diameter of a carbon atom is 0.15 nm , calculate the no. of carbon atoms which can be placed side by side in a straight line across a length of scale of length 20 cm long. plz tell me ..

Answer 1

Explanation:

0.15nm =15×10-11m= 15×10-9 cm

totally 20 cm scale. so

n × 15 × 10-9= 20× 10-2

n×3×10-7=4

n=4/3×10+7

n= 1.33× 10+7

n=13333333.