Question

if diameter of a road roller is 0.9m & its length is 1.4 m, how much area of a field will be pressed i its 500 rotations ?

Answer 1

length is 1.4m
diameter is 0.9m, radius=0.9/2=0.3m
area of field pressed in 500 rotations = (2×22/7×0.3 ×1.4×500)m^2
=1320m^2

hope this helps you :-)

Answer 2

Answer:

$\text{Area covered by the roller in 500 revolutions =}1980 m^2$

Step-by-step explanation:

Given diameter of a road roller is 0.9 m and its length 1.4 m.

we have to find the area of a field will be pressed its 500 rotations.

Diameter, d = 0.9 m

Radius, r = 0.45 m

Length of the roller = 1.4 m

$\text{Area covered by roller in 1 revolution = Curved surface area of the roller}$

                                                      $= 2\pi rh$

                                                       $=2 \times \frac{22}{7} \times 0.45 \times 1.4$

                                                       $= 3.96 m^2$

$\text{Area covered by the roller in 500 revolutions =}22 \times 500 =1980 m^2$