Question

if diameter of a road roller is 0.9m and its length is 1.4m, how much area of field will be pressed in its 500 rotations?​

Answer 1

Answer:

The area pressed will be 565.714m.

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Step by step explanation:

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Given:

radius(r) of roller = 0.9m

length(h) of roller =1.4m

To find:

area pressed in 500 rotations=?

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area pressed in 1 rotation= 2Πrh

area pressed in 500 rotations= 2Πrh×500

$= > 2 \times \frac{22}{7} \times 0.2 \times 0.9 \times 500 \\ = > 2 \times \frac{22}{7} \times \frac{2}{10} \times \frac{9}{10} \times 500 \\ = > 2 \times \frac{22}{7} \times 2 \times 9 \times 5 \\ = > \frac{3960}{7} \\ = > 565.714m.$

Hence, the area of field pressed in 500 rotations will be 565.714m.

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