if diameter of increase by 40% .find by how much % ratio increase
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Answer:
If original diameter = 2x ,
original radius = x
So, original area = pi x²……….(1)
Increase in diameter = 40% of original diameter = 40/100 * 2x
= 4x/5
New diameter= 2x + 4x/5
= 14x/5
New radius = 7x/5
New increased area = pi 49x² /25 ……….(2)
So, increase in area = pi x² ( 49/25 — 1)
= 24x²pi /25
percentage increase =
[(increase in area)/ original area ] * 100
= {(24x²pi/25) / pi x² }*100 = ( 24/25)*100
= 24*4 = 96
Increase in area = 96%
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