Question

if different values of variable x are 9.8,5.4,3.7,1.7,1.8,2.6,2.8,8.6,10.5and 11.1
find the mean of x
and the value (x-x)

Answer 1

Answer:

0

Step-by-step explanation:

Given different values of variable xi are 9.8,5.4,3.7,1.7,1.8,2.6,2.8,8.6,10.5 and 11.1

Mean = x1 + x2 + x3.......................+xn / n

       x   = 9.8 + 5.4 + 3.7 + 1.7 + 1.8 + 2.6 + 2.8 + 8.6 + 10.5 + 11.1 / 10

Mean = 5.8

Now Σ(xi - x) = (x1 - x) + (x2 - x)+--------------------(xn - x)

                  = (9.8 - 5.8) + (5.4 - 5.8) + (3.7 - 5.8) + (1.7 - 5.8) + (1.8 - 5.8) + (2.6 - 5.8) + (2.8 - 5.8) + (8.6 - 5.8) + (10.5 - 5.8) + (11.1 - 5.8)

We get 0 on subtracting.

Answer 2

Answer:

$Given different values of variable xi are 9.8,5.4,3.7,1.7,1.8,2.6,2.8,8.6,10.5 and 11.1Mean = x1 + x2 + x3.......................+xn / n x = 9.8 + 5.4 + 3.7 + 1.7 + 1.8 + 2.6 + 2.8 + 8.6 + 10.5 + 11.1 / 10Mean = 5.8Now Σ(xi - x) = (x1 - x) + (x2 - x)+--------------------(xn - x) = (9.8 - 5.8) + (5.4 - 5.8) + (3.7 - 5.8) + (1.7 - 5.8) + (1.8 - 5.8) + (2.6 - 5.8) + (2.8 - 5.8) + (8.6 - 5.8) + (10.5 - 5.8) + (11.1 - 5.8)We get 0 on subtracting.$

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