If dimension of a rectangular ground is 42 m x 66 m. Out side the ground,
around it, a cemented path of width 2 m is made. If 1 bag of cement is
required for 4 m2 path. Find how many bags of cement will be needed to
construct the path? If 4 rounds of barbed wire is used to fence the ground
(not the road) what will be the cost of wire if 1 m. barbed wire is costing
Rs. 50.
Answers
Solution :
The given dimensions of the rectangular grounds are 42 m × 66 m .
Outside the ground, around it, a cemented path of width 2 m is made.
Area of the cemented path :
=> Total area including the path - Area of the ground
=> 46 × 70 - 42 × 66
=> 448 m²
Amount of cement required :
=> 448 / 4'
=> 112 bags of cement .
Perimeter of the road :
=> 2 ( 46 + 70 )
=> 232 m
Cost of fencing ;
=> 232 × 4 × 50
=> Rs. 46400
This is the required answer.
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Step-by-step explanation:
dimension of rectangular garden = 42*66
cemented path area = 2m above length 2m below length. 2m above breadth. 2m below breadth.
total cement area =46*70
bags required= total area including path - area og ground.
46*70 - 42*66
=448msquare.
1bag of cement=4msquare.
total bag of cement= 448/4=112.
total 112 bags.
for fencing the ground=42*66
perimeter of garden=2(l+b)
2*108=216.
4rounds =216*4=864m.
1m=rupees 50.
total cost = 864*50= rupees 43200
total cost = 43200