If dimensions of the length are expressed as G*C'h' where G, C and h are universal gravitational constant and speed of light and Planck's constant respectively, then
Answers
Answered by
0
Answer:
(M
0
L
1
T
0
) αG
x
l
y
h
z
G=
M
2
(M
1
L
1
T
−2
)
×(L
2
)=M
−1
L
3
T
−2
C=LT
−1
h=
λ
C
Energy
=
L
LT
−1
M
1
L
2
T
−2
=M
1
L
2
T
−1
M
0
L
1
T
0
=(M
−1
L
3
T
−2
)
x
(LT
−1
)
y
(M
1
L
2
T
−1
)
z
−x+z=0,3x+y+2z=1,−2x−y−z=0
x=z
⇒5x+y=1
y=−3/2
x=1/2
z=1/2
Answered by
0
Explanation:
Correct option is
C
x=21,y=−23,z=21
Length ∝GxCyhz
[L]=[M−1L3T−2]x[LT−1]y[ML2T−1]z
On comparing the power of M, L and T in both sides, we get
−x+z=0 ....(i)
3x+y+2z=1 ....(ii)
and −2x−y−z=0 ....(iii)
By solving Eqs. (i), (ii) and (iii) we get
x=21;y=−23 and z=21
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