Question

If dipole moment is 10Cm and electric field is 20 N/C, find the potential energy at stable equilibrium​

Answer 1

Given that ,

Dipole moment (P) = 10 C•m

Electric field (E) = 20 N/c

We know that ,

The potential energy of dipole in a electric field is given by

$\large \sf \fbox{U = - PE × Cos( \theta)}$

Where ,

Φ = angle between P and E

Thus ,

U = -10 × 20 × Cos(0)

U = -200 × 1

U = -200 Joule

$\therefore \sf \underline{The \: potential \: energy \: of \: dipole \: is -200 \: J}$

Remmember :

At stable equilibrium , the angle between P and E is 0

At unstable equilibrium , the angle between P and E is 180