Question

. If dipole moment of H-Cl is 3.2x10-31 Coulomb-metre. Find out the percentage ionic character if intermolecular distance is 1 A° ?

Answer 1

Answer:

2%

Explanation:

U = 3.2 X 10^ -31 Cm

d= 10^-10 m

U = q X d

Therefore,

3.2 X 10^-31 / 10 X 10^-10 = q

q= 3.2 X 10^ -22 C

Now charge of one electron in SI system is 1.6 X 10^ -19 C

Therefore electronic charge = 3.2 X 10^ -10 / 1.6 X 10^-19 X 100

= 2%

Hence the percentage ionic character is 2%.

I hope you understand the answer.