Question

If discriminant of quadratic equation mx? - 4x + 7 = 0 is –68, then value of 'm' is​

Answer 1

Step-by-step explanation:

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Answer 2

Given,

A quadratic equation: mx^2 - 4x + 7 = 0

To find,

The value of m.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

In a quadratic equation: ax^2 + bx + c = 0, the nature of its roots is determined by the value of discriminant D = (b^2-4ac), as follows:

a) if D>0, then real and distinct roots

b) if D=0, then real and equal roots

c) if D<0, then complex and distinct roots

{Statement-1}

Now, according to the question;

For the given quadratic equation; mx^2 + (-4)x + (7) = 0

The value of a = m

Value of b = (-4)

Value of c = (+7)

According to the question;

The value of discriminant, D = (-68)

=> (b^2-4ac) = (-68)

{according to statement-1}

=> (-4)^2 - 4(m)(7) = (-68)

=> 16 - 28m = -68

=> 28m = 16 + 68 = 84

=> m = (84)/(28) = 3

=> m = 3

Hence, the value of m is 3.