If displacement of a body is given by x = 3t3 + 4t2 – 2. Find velocity & acceleration at 2sec. Also
comment the nature of acceleration of the body.
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Answer:
Given displacement x=5+3t+2t
2
Differentiating the above equation with respect to time t we get velocity of the body
v=
dt
dx
=3+4t
Now again differentiating the velocity with respect to time we get acceleration
a=
dt
dv
=4
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