if displacement of a body s=(200±5)m and time taken by it T =(20±0.2)m.find the percentage error in the calculation of velocity
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we know that,speed=distance/time
I.e,v=s/T
∆v/v *100= ∆s/s*100 + ∆t/t*100
∆v/v*100=5/200*100+0.2/20*100
=(5/200+0.2/20)*100
=(2.5+1)
=3.5%,can be +ve or - ve
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