if displacement of a body s = (200+_ 5 )meter and time taken by it is t= (20+_0.2)seconds then find the percentage error in the calculation of velocity?
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Answered by
164
Answer:
3.5%
Explanation:
In this question
s = 200
t = 20
Δs = 5
Δt = 0.2
We know that displacement = velocity × time
∴ s = v × t
For error in velocity we know that
Δv/v = Δs/s + Δt/t
or, Δv/v = 5/200 + 0.2/20
or, Δv/v = 0.025 + 0.01
= 0.035
∴ Percentage error in velocity = 0.035 × 100 = 3.5%
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