if displacement of a particle is x^2=at^2+2bt+c, then what will be its acceleration?
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By differentiation we get
2xdx/dt=2at+2b
xdx/dt=at+b
This gives the equation of velocity
Now differentiating again
d/dt(dx/dt) =d/dt((at+b) /x))
Which I think you can simplify...
2xdx/dt=2at+2b
xdx/dt=at+b
This gives the equation of velocity
Now differentiating again
d/dt(dx/dt) =d/dt((at+b) /x))
Which I think you can simplify...
aryav1:
thanks
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