Question

if displacement of a particle is x=av^2 +b,a and b are constants ,then the. acceleration of the particle is

Answer 1

which class u r studying in

Answer 2

Answer:

Velocity =v=

dt

dy

=b+2ct−4dt

3

v

0

=b+2c(0)−4d(0)

3

=b (for initial velocity, t=0)

And acceleration =a=

dt

dv

=2c−12dt

2

∴ Initial acceleration =a

0

=2c−12d(0)

2

=2c