Question

If displacement of an object is x=30+20t² than its acceleration will be​

Answer 1

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If displacement of an object is x=30+20t² than its acceleration will be ?

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• The acceleration of the object is x = 30 + 20t²

$\longrightarrow$ $\frac{(30 + 20t {}^{2}) }{ {t}^{2} }$

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$\large{\underline{\underline{\sf{\red{\frac{30}{ {t}^{2} + 20}}}}}}$

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Answer 2

Answer:

Double differentiation of displacement gives acceleration.

So dx/dt= velocity (v) = 40t

dx²/ d²t = acceleration (a) = 40 m/s²

POINTS TO KEEP IN MIND:

• The differentiation of a constant (without an associated variable) is always zero.
• The common formula of differentiation is nˣ = xnˣ⁻¹ where n= variable, x= its power.
• If a constant is associated with a variable, as in 30t³, its differentiation becomes (3 × 30)t³⁻¹ = 90t².