Question

If displacement of simple pendulum at any time is 0.02m and acceleration is 2m/s2, then in this time angular velicity will be

Answer 1

For small displacement , motion of simple pendulum is the example of Simple harmonic motion . so, Acceleration , α = ω²A ,
Here ω is angular frequency and A is maximum displacement .

Here, α = 2 m/s² , A = 0.02 m
∴ ω² = α/A = 2/0.02 = 100
⇒ ω = 10 rad/s

Hence, angular frequency = 10 rad/s