Question

If \displaystyle \sin A + \sin^2 A = 1sinA+sin2A=1 and \displaystyle a \cos^{12} A + b \cos^8 A + c \cos^6 A - 1 = 0acos12A+bcos8A+ccos6A−1=0 then \displaystyle b+\frac{c}{a}+b = ?b+ac​+b=?​

Answer 1

Answer:

If \displaystyle \sin A + \sin^2 A = 1sinA+sin2A=1 and \displaystyle a \cos^{12} A + b \cos^8 A + c \cos^6 A - 1 = 0acos12A+bcos8A+ccos6A−1=0

then a+b+c= 5