Question

If \\displaystyle{u=2x+3y^2-2^2,v=x^2-3y+z^2,w=2X^2+y^2-22}\), then \(\displaystyle{\frac{\partial {\left(u,v,w\right)}}{\partial {(x,y,z)}}}\) at \(\displaystyle{0,2,1)}\) is
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Answer 1

Step-by-step explanation:

\displaystyle{u=2x+3y^2-2^2,v=x^2-3y+z^2,w=2X^2+y^2-22}\), then \(\displaystyle{\frac{\partial {\left(u,v,w\right)}}{\partial {(x,y,z)}}}\) at \(\displaystyle{0,2,1)}\) is