Question

If distance between the lines (x-2y)^2+k(x-2y)=0 is 3 then k = ?

Answer 1

SOLUTION

$= > (x - 2y) {}^{2} + k( x - 2y + k) = 0 \\ \\ = > ( {x - 2})</u><u>[</u><u>x</u><u> - 2y + k</u><u>]</u><u> = 0 \\ = > x - 2y = 0 \: \: or \: \: x - 2y = - k \\ = > </u><u>D</u><u>istance (d) = | \frac{k}{ \sqrt{1 + 4} } | = 3 \\ = > | \frac{k}{ \sqrt{5} } | = 3 \\ = > k = 3 \sqrt{5}$

hope it helps ☺️