Question

if distance between the points(4,k) and (1,0) is 5,then what can be the possible value of k?

Answer 1

By distance formula,

d =√{(4-1)²+(k-0)²}

5=√{3² +k²}

5² =9+k²

25=9+k²

25-9 =k²

16=k²

√16 =k

4 =k


Then value of k is 4


I hope this will help you

-by ABHAY

Answer 2

distance =root [(4-1)+k]
5=root [(3+k)]
25=3+k
k=22