Question

If distance between the points (x,-1) and (3,2) is 5 then one of the possible values of x is...​

Answer 1

Answer:

If distance between the points (x,-1) and (3,2) is 5 then one of the possible values of x is

Answer 2

Hello, Buddy!!

||Required Response||

$\sqrt{ {(3 - x)}^{2} + {(2 - ( - 1))}^{2} } = 5 \\ by \: squaring \: on \: both \: sides \\ ( { \sqrt{ {(3 - x)}^{2} + {(2 + 1)}^{2} } })^{2} = {(5)}^{2} \\ {(3)}^{2} + {x}^{2} - 2(x)(3) + {(3)}^{2} = 25 \\ {x}^{2} - 6x + 9 + 9 = 25 \\ {x}^{2} - 6x + 18 - 25 = 0 \\ {x}^{2} - 6x - 7 = 0 \\ {x}^{2} - 7x + x - 7 = 0 \\ x(x - 7) + 1(x - 7) = 0 \\ (x - 7)(x + 1) = 0 \\ x = 7 \: (or) \: - 1$

Required Value of x

• $\longmapsto\;\red{\bold{7\;\&\;-1}}$

$\boxed{\sf{Distance\; between\;two\; points = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}}}$

$\boxed{\tt{@MrMonarque♡}}$

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