if distance between two points (2,-3) and (5,a) then find the value of a.
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a = 1
Explanation :
Let the two points be A(2,−3) and B(5, a)
∣ A − B ∣ = 5
⟹ ∣ A − B ∣² =25
⟹ ( 2 − 5 )² +( −3 −a)² =25
⟹ 9 + 9 + 6a + a² = 25
⟹ a² + 6a − 7 = 0
⟹ a²+ 7a − a−7 = 0
⟹ ( a + 7 ) ( a − 1 ) = 0
⟹ a = −7 or a = 1
But distance can't be negative
Hence a = 1
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