if distance between two poles in the ground is 8 meter and their height are 10 cm and 6 cm then find the distance between their tops
Answers
Answer:
That's hope it helps you
Answer:
4√5
Step-by-step explanation:
Given: height of first pole = AB = 6m
Height of second pole = CD = 10m
Distance b/w feet of poles = AC = 8m
To find:- Distance b/w the top of the poles , i.e.,BD
solution :-
let we draw a line BE perpendicular to DC i.e BE DC
since AC is also perpendicular to DC as pole is vertical to ground,
So, BE=AC=8m
Similarly , AC=EC=6m
Now,
DE=DC-EC
DE=10-6
DE=4M
Since angle BED = 90o as BEperpendicular DC
Triangle BED is right triangle
Using pythagoras therom in right angle triangle AEB
(hpotenuse)2 = (height)2 +(base)2
(BD)2 = (4)2 +(8)2
(BD)2 = 16+64
(BD)2 = 80
BD = 4√5
Hennce, the distance b/w tops of the pole = 4√5 meter
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