Question

If distance of a point in a plane from x and y axis are 3 and 5 respectively then find the coordinates​

Answer 1

$\mathbf\purple{{Explaination\::-}}$

Given,

x=5,y=−9

∴ coordinates of P and Q are (5,0) and (0,−9) respectively

d(P,Q)=Distance between P and Q

=(5−0)2+(0−(−9))2

=52+92

=25+81

=106

=10.29 units

Answer 2

Answer:

Given,

x=5,y=−9

∴ coordinates of P and Q are (5,0) and (0,−9) respectively

d(P,Q)=Distance between P and Q

=

(5−0)

2

+(0−(−9))

2

=

5

2

+9

2

=

25+81

=

106

=10.29 units

solution

Step-by-step explanation:

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