Question

If distance of a point k,4 from origin is 5units then find the value of k

Answer 1

distance = root [(k-0)^2 + (4-0)^2]

5 = root [k^2 + 4^2]

5^2 = k^2 + 16

25 = k^2 + 16

25-16 = k^2

9 = k^2

root 9 = k

3= k

Then the value of k is 3


i hope this will help you

-by ABHAY

Answer 2

the answer to the question is k=3