Question

If distance travelled is s at time t and ifs=4t+2t2 then
calculate initial velocity and acceleration

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Answer 1

Answer:

here,

s=4t+2t²

differenciating both sides with respect to time

ds/dt=4+4t

v=4+4t..............(1)

initial velocity at t=0 is

v=4+4*0=4m/s

differenciating (1) with respect to time

dv/dt=4

or,a=4

so initial acceleration is 4m/s²