if dividend and divisor are 9x^3-5x^2+2x+3 and 3x^2+5 respectively,then the first term of the quotient is
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If we divide f(x)=3x3+x2+2x+5 by g(x) we get q(x)=(3x−5) as quotient and r(x)=(9x+10) as remainder.
By using division algorithm,
f(x)=g(x)q(x)+r(x)
⟹3x3+x2+2x+5=g(x)(3x−5)+(9x+10)
⟹g(x)=(3x−5)3x3+x2+2x+5−9x−10
⟹g(x)=(3x−5)3x3+x2−7x−5
Hence, g(x)=x2+2x+1
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