Question

If dividend = x3 + 4x2- cx + 8, divisor = x - 2 and remainder = 0, then the value of c is
cis
1) 18
2) 14
3) 16
4) 20
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Answer 1

Answer:

x-2=0

x=2

p(x)=2^3+4*2^2-C*2+8 =0

= 8+16-2C+8=0

=24-2C+8=0

=32-2C=0

=-2C=-32

=C=-32/-2

=C=16

So answer is 16 (3)

Answer 2

Answer:

14

Step-by-step explanation:

x - 2 = 0

X= 2

By remainder theorem,

p(X) = x³+4x²- cx+ 8

p(2) = (2)² + 4(2)²-c(2) +8

= 4 + 16 - 2c + 8

= 28 - 2c

28 - 2c = 0

- 2c = - 28

c = - 28/-2

= 14

Hope this helped you......