If divisor of f(x) =2x-a is (x-a) then find the value of remainder.
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f(x)=(x−a)q(x)+r(x)
where, q(x) is the quotient when f(x) is divided by x−a and r(x) is the remainder.
The Remainder Theorem says that we can restate the polynomial in terms of the divisor, and then evaluate the polynomial
x=a
⇒f(a)=0×q(a)+r(a)
⇒f(a)=r(a)
Hence, the remainder is f(a).
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where, q(x) is the quotient when f(x) is divided by x−a and r(x) is the remainder.
The Remainder Theorem says that we can restate the polynomial in terms of the divisor, and then evaluate the polynomial
x=a
⇒f(a)=0×q(a)+r(a)
⇒f(a)=r(a)
Hence, the remainder is f(a).
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Answer:
=-3a
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