If divisor of f(x) is x + a then find the remainder.
i) f(x) = x² - a²
ii) f(x)= 2x - a
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Given
- f(X) = X+a
- it is a divisor
To find
The remainder
i) f(x) = x² - a²
ii) f(x)= 2x - a
Solution
From remainder theorem
X+a =0
=>X= -a
- f(X)= x² - a²
f(-a)= a - a²
=0
- The remainder is 0
2).f(x)= 2x - a
f(-a) = -2a-3a
= -5a
- The remainder be -5a
Hence, values are 0,-5a
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