If domain of f(x) is [1, 2], then the domain of 2 f log x is
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you mean, " if domain of f(x) is [1, 2] , then the domain of 2f(logx) is " right ?
you should understand that, domain of f(x) = domain of kf(x)
e.g., domain is independent of coefficient of f(x).
so, domain of f(logx) = domain of 2f(logx)
now, as ' logx ' in place of 'x'
so, 1 ≤ logx ≤ 2
or, 10¹ ≤ x ≤ 10²
hence, 10 ≤ x ≤ 100
so, domain of 2f(logx) [10, 100]
you should understand that, domain of f(x) = domain of kf(x)
e.g., domain is independent of coefficient of f(x).
so, domain of f(logx) = domain of 2f(logx)
now, as ' logx ' in place of 'x'
so, 1 ≤ logx ≤ 2
or, 10¹ ≤ x ≤ 10²
hence, 10 ≤ x ≤ 100
so, domain of 2f(logx) [10, 100]
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