If domation of f(x)= x-3 is (0,3,6)then find its range x+4
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Answer:
f(x)=
x−3
∣x−3∣
x−3
=0 (Denominator cannot be zero)
⇒x
=3
∴ Domain: R−{3}
f(x)=
⎩
⎪
⎪
⎨
⎪
⎪
⎧
(x−3)
(x−3)
=1;
−
x−3
(x−3)
=1;
x>3
x<3
∴f(x)={
1;
−1;
x>3
x<3
∴Range ={−1,1}.
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