If double the second term of an A.P is equal to 5 times its fifth term. Then show that 7th term of A.P is zero.....
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Answered by
18
Given: 2(a2)=5(a5)
So, 2(a+d)=5(a+4d)
2a+2d=5a+20d
-3a=18d
a=-6d
To prove : a7=0
a+6d=0
-6d+6d=0
0=0
So, 2(a+d)=5(a+4d)
2a+2d=5a+20d
-3a=18d
a=-6d
To prove : a7=0
a+6d=0
-6d+6d=0
0=0
Answered by
3
2a+2d=5(a+4d)
2a+2d=5a+20d
2a-5a=20d-2d
-3a=18d
a= -6d
a+6d=0
-6d+6d=0
0=0
2a+2d=5a+20d
2a-5a=20d-2d
-3a=18d
a= -6d
a+6d=0
-6d+6d=0
0=0
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