If dx/(2+18x2) = pie/24
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Answered by
0
Answer:
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Answered by
1
Answer:
2+18x
2
dx
⟹
2
1
∫
0
k
1+(3x)
2
dx
⟹
6
1
[tan
−1
(3x)]
0
k
⟹
6
tan
−1
(3k)
=
24
π
⟹tan
−1
(3k)=
4
π
⟹3k=1
⟹k= 1_3
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