Question

If dy/dx=x2+y and y(0)=1 find (y) at x=1.5 (use range kutta method. h=0.5​

Answer 1

Answer:

dy/dx=x^2+y

y=0, x=0

d(0) /d(1.5)=(1.5)^2+0

0/0=1.5×1.5

=2.25

d=2.25