Question

If e=(3i^+6j^+4k^)n/c,calculate the electric flux through a surface area of 20cm2 in y-z plane

Answer 1

it should be the required answer

Answer 2

The electric flux through the surface is $0.006\ N/Cm^2$.

Explanation:

Electric field, $E=(3i+6j+4k)\ N/C$

Area, $A=20\ cm^2=0.002\ m^2$

Area vector in y-z plane is, $A=0.002i\ m^2$

To find,

Electric flux

Solution,

The product of electric field and the area vector is called electric flux. It is given by :

$\phi=E{\circ}A$

$\phi=(3i+6j+4k).(0.002i+0j+0k)$

$\phi=0.006\ N/Cm^2$

So, the electric flux through the surface is $0.006\ N/Cm^2$.

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Electric flux

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