if E and F are the points on diagnol AC of a parallelogram ABCD such that AE=CF,then show that BFDE is a parallelogram
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GIVEN - ABCD IS A PARALLELOGRAM
AE=CF
TO PROVE THAT - BFDE IS A PARALLELOGRAM
PROOF - IN Δ AED N Δ BFC
AD=BC (OPP. SIDE OF PARALLELOGRAM)
ANG. DAE = ANG. BCF (ALTERNATE INTERIOR ANGLE)
AE= CF (GIVEN)
BY SAS CONG.
ΔAED IS CONG. TO Δ BFC
DE= BF (CPCT)
SLY, IN ΔDFC N Δ BEA
DF= BF (CPCT)
SINCE OPP. SIDES R EQUAL
N IN A PARALLELOGRAM, OPP. SIDES R EQUAL...
SO, BDEF IS A PARALLELOGRAM.....
HOPE IT WORKS..... THNK U
AE=CF
TO PROVE THAT - BFDE IS A PARALLELOGRAM
PROOF - IN Δ AED N Δ BFC
AD=BC (OPP. SIDE OF PARALLELOGRAM)
ANG. DAE = ANG. BCF (ALTERNATE INTERIOR ANGLE)
AE= CF (GIVEN)
BY SAS CONG.
ΔAED IS CONG. TO Δ BFC
DE= BF (CPCT)
SLY, IN ΔDFC N Δ BEA
DF= BF (CPCT)
SINCE OPP. SIDES R EQUAL
N IN A PARALLELOGRAM, OPP. SIDES R EQUAL...
SO, BDEF IS A PARALLELOGRAM.....
HOPE IT WORKS..... THNK U
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