if e,f,g and h are respectively the mid points of the sides ab,bc, cd, and ad of a parallelogram abcd, show that ar (efgh )1/2 ar(abcd )
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E is the mid point of AB
And F is also the mid points
//ly H and G also mid points
So draw a line and
Abcd =1/2 of ∆efg-1
//ly ∆ehg =1/2 of abcd-2
Add 1&2 from this
Efgh=1/2 abcd
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