Question

If E is a point on side QR of ∆PQR, Such that PE bisects ∠QPR, then

Answer 1

Answer:I hope it helps

Step-by-step explanation:

Here , ∠ QPE = ∠ RPE --- ( 1 )

And from exterior angle theorem we get :

∠ PEQ = ∠ RPE + ∠ PRE , Substitute value from equation 1 we get :

∠ PEQ = ∠ QPE + ∠ PRE

From above equation we can say that :

∠ PEQ > ∠ QPE

And we know in any triangle side opposite greater angle is greater .

So,

QP > QE

Therefore,