Question

if E is the energy density in an ideal gas, then tha pressure of the ideal gas is

Answer 1

An ideal gas is said to follow the ideal gas law perfectly and it has a simplified equation of state. The ideal gas law is usually depicted by the equation - 

PV = nRT.

According to the kinetic theory of gases, the potential energy is zero and the gases have just Kinetic energy. So, E = 3/2 RT.

By using this equation, we can get E = 3/2 P.

So, P (pressure) = 2/3 E.

Answer 2

Energy density=Energy/Volume

=U/V

=E (given)

We know that, energy of n mole of a gas

=U=nfRT/2

For a monoatomic gas, f=3

=> U=3/2 × nRT

=> U=3/2 × PV [nRT=PV]

=> P=2/3 × U/V

=> P=2/3 E

I hope that you all were able to understand the solution bcoz i tried to explain well:)