Question

If e^log (x^2)=-1 then find the value of x?

Answer 1

$e ^{log_e (x^{2}) } =-1 \\ \\ x^{2} =-1 \\ \\ x=+i\ and\ -i$

Answer 2

e^log (x^2)=-1
x^2=-1
x= + or - √-1
x= + or - i
Therefore, x=i or -i