Question

If E, M, J and G, respectively, denote energy, mass, angular momentum, and gravitational constant, then EJ2/M5G2 has the dimensions of

Answer 1

Answer:

Dimension-less quantity.

Explanation:

$E=ML^2T^-^2\\\\L=ML^2T^-^2\\\\G=M^-^1L^3T^-^2$

$\boxed{\frac{FL^2}{M^5G^2}}$

$\boxed{\frac{(ML^2T^-^2)(ML^2T^-^1)^2}{M^5(M^-^1L^3T^-^2)^2}}$

$\boxed{\frac{(ML^2T^-^2)(M^2L^4T^-^2)}{M^5(M^-^2L^6T^-^4)} }$

$Here\ the\ numerator\ and\ denominator\ gets\ cancelled.$

So, it is a dimension-less quantity.

Answer 2

See the attachment mate

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