Question

If E(Y) = 3 where Y= (X-2)/5 , then E(X) is​

Answer 1

Answer:

Y 5

Explanation:

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Answer 2

Answer:

Required value of E(x) is 17.

Explanation:

Here given function is E(y).

Value of E(y) is 3.

Now given equation is

$y = \frac{x - 2}{5}$

Here y and x are variable.This a linear equation because highest degree of variable is 1.

We are taking E function in both side of the equation.

$E(y )=E( \frac{x - 2}{5} )$

$E(y) = \frac{E(x - 2)}{E(5)}$

$E(y) = \frac{E(x) - 2}{E(5)}$

$E(y) = \frac{E(x) - 2}{5} ......(1)$

Because

$E(5) = 5 \: \: \: and \: \: E(2) = 2$

Now we know

$E(y) = 3$

Now from equation (1),

$3 = \frac{E(x) - 2}{5}$

By cross multiplication,

$E(x) - 2 = 3 \times 5$

We are multiplying 3 and 5,

$E(x) - 2 = 15$

$E(x) = 15 + 2$

We are adding 15 and 2,

$E(x) = 17$

So value of E(x) is 17.